Given: MP bisects LMN, LM = NM Prove: LP = NP ~ ~ P N M L. 3 Given: HJ LK, JK HL Prove: H = K ~ H L K J. 4 Given: MS TR, MS = TR Prove: A is the midpoint of MT ~ M S

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Correct answer to the question: MO bisects < LMN. The < LMO = 7x-23 and

bisects ∠LMN,  Ray MO bisects ∠LMN, m∠LMO=8x−23, and m∠NMO=2x+37. Solve for x and find m∠LMN. The diagram is not to scale. 2. Ray MO bisects ∠LMN,  Ray MO bisects <LMN.

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58. angle 1 and angle 2 are a linear pair. angle 1 = x - 30, and angle 2 = x + 76. Find the measure of each angle.

Mo rightarrow bisects LMN, m LMO = 6x - 20, a nd m NMO = 2x + 36. Solve for x and find m LMN the diagram is not to scale x = 13, m LMN = 116 x = 13, m LMN = 58 x = 14, m LMN = 128 x = 14, m LMN = 64

ALMOSANOM 4. AAS. 6.

1 Oct 2011 m< NMO = m< LMN - m< LMO = (5x - 23) - (x + 32) = 5x - 23 - x - 32 = 4x - 55. Since

2, 7° c. 7 MO → bisects ∠LMN, m∠LMN = 5x − 23, m∠LMO = x + 32.

Mo bisects lmn

geometry In the figure (not drawn to scale), MO bisects LMN, MZLMO = (13x – 31), and MZNMO = (x + Related Posts. Genel. Express the product of 2x^2+6x-8 and x+3 in standard Line MO bisects angle LMO, angle LMO=8x-20, and angle NMO=3x+30.
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Find the measure of angle 3. Given: 71Z1 = (6x + 40)" and m/2 = (9x + 4).

–1 c. 2.5 d.
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2012-08-27

(14, 12) d Given: MO −→− bisects ∠LMN m∠LMO = 6x−20 m∠NMO = 2x+36 Solve for x and find m∠LMN. The diagram is not to scale. Question options: m∠LMN = 64 m∠LMN = 58 m∠LMN = 116 m∠LMN = 128 Question 15 5/5 Points How are the two angles related? Q. Ray MO bisects ∠LMN, m∠LMO = 6x - 20, and m∠NMO = 2x + 36. Solve for x and find m∠LMN.

If m∠DEF = 122, then what are m∠FEG and m∠HEG? The diagram is not to scale. 5. MO. →. bisects ∠LMN, 

22. 2(X+31)  If m∠DEF = 122, then what are m∠FEG and m∠HEG? The diagram is not to scale. 5.

Find m∠NMO. I don't know how to combat this problem. Please help!!!